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limit as x approaches infinity of (ln(x))/x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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prove cos(x)1−sin(x) =sec(x)+tan(x)

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{sin(x):x<0, 2x:x≥ 0}

הגדרת נקודה החשודה כקיצון

נקודדות חשודות הן נקודות בהן הפונקציה מוגדרת והנגזרת בנקודה שווה לאפס או לא מוגדרת

{sin(x):x<0} נקודת חשודות של: x=π2 +2πn, x=3π2 +2πn

{2x:x≥ 0} נקודת חשודות של: אין

:אחד את כל הנקודות החשודות של כל חלקי הפונקציה

x=π2 +2πn, x=3π2 +2πn

x=0 חשב את נקודת הקצה של האינטרוול: critical point

x=π2 +2πn, x=3π2 +2πn, x=0

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

limit as x approaches infinity of (ln(x))/x

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