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foci ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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center (x−1)²9 +y²5 =100

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(1, 0)

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(x−1)²9 +y²5 =100

משוואה סטנדרטית של אליפסה

היא המשוואה הסטנדרטית של האליפסה (x−h)²a² +(y−k)²b² =1
a, b וצירים ראשיים ומשניים (h, k) עם מרכז

בצורה של משוואת האליפסה הסטנדרטית (x−1)²9 +y²5 =100 שכתב את

(x−1)²30² +(y−0)²(10√5)² =1

:לכן מאפייני האליפסה הם

(h, k)=(1, 0), a=30, b=10√5

הוא ציר חצי-משני b הוא ציר חצי-ראשי ו a לפיכך a>b

b=10√5 וציר משני a=30 ציר ראשי (h, k)=(1, 0) אליפסה עם מרכז

:והמרכז הוא

(1, 0)

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היי, לשאול שאלה לגבי center (x−1)²9 +y²5 =100 או בחר למטה

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

foci ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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