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inverse of x^2+(y+3)^2=16

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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factor lim_{x→ −5}(x²−25x²+4x−5 )

Solution

Decimal

1.66666…

Mixed Number

123

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Solution steps

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lim_{x→ −5}(x²−25x²+4x−5 )

x²−25x²+4x−5 פשט את: x−5x−1

=lim_{x→ −5}(x−5x−1 )

x=−5 הצב את הערך

=−5−5−5−1

−5−5−5−1 פשט את: 53

=53

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of x^2+(y+3)^2=16

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