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vertices -((x+3)^2)/(20)+1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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next term a_n=4(−2)ⁿ⁻¹

Solution

a₁=4

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Function Inverse definition

A function g is the inverse of function f if for y=f(x), x=g(y)

y=−(x+3)²20 +1

Replace x with y

x=−(y+3)²20 +1

Solve for y, x=−(y+3)²20 +1

√−20x+20−3, −√−20x+20−3

Solve instead

sequence type a_n=4(−2)ⁿ⁻¹

first term a_n=4(−2)ⁿ⁻¹

nth term a_n=4(−2)ⁿ⁻¹

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היי, לשאול שאלה לגבי next term a_n=4(−2)ⁿ⁻¹ או בחר מבין האפשרויות למטה

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices -((x+3)^2)/(20)+1

Solution

Solution steps

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