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axis y=-((x+3)^2)/(20)+1

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axis y=−(x+3)²20 +1

Solution

x=−3

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y=−(x+3)²20 +1

Parabola standard equation

4p(y−k)=(x−h)² is the standard equation for an up-down facing parabola with vertex at (h, k),
and a focal length |p|

Rewrite y=−(x+3)²20 +1 in the standard form: 4(−5)(y−1)=(x−(−3))²

Therefore parabola properties are:

(h, k)=(−3, 1), p=−5

Parabola is of the form 4p(y−k)=(x−h)² and is symmetric around the y-axis
Axis of symmetry is a line parallel to the y-axis which intersects the vertex:

x=−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

axis y=-((x+3)^2)/(20)+1

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