integral of cos(2x+1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx (arctan(−x))

Solution

−1x²+1

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ddx (arctan(−x))

השתמש בחוק השרשרת: 1(−x)²+1 ddx (−x)

=1(−x)²+1 ddx (−x)

ddx (−x)=−1

=1(−x)²+1 (−1)

1(−x)²+1 (−1) פשט את: −1x²+1

=−1x²+1

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היי, לשאול שאלה לגבי ddx (arctan(−x)) או בחר מבין האפשרויות למטה

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of cos(2x+1)

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