amplitude of cos(2x+5)

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foci y=−3x²−2x+65

Solution

(−13 , 1720 )

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מוקדי הפרבולה

פרבולה היא המיקום של נקודות כך שהמרחק לנקודה (המיקוד) שווה למרחק לקו - הכיוון

משוואה סטנדרטית של פרבולה

היא המשוואה הסטנדרטית של פרבולת מעלה-מטה 4p(y−k)=(x−h)²
|p| ואורך מוקד

בצורה סטנדרטית y=−3x²−2x+65 שכתב את

4(−512 )(y−1915 )=(x−(−13 ))²

(h, k)=(−13 , 1915 ), p=−512

לאורך הציר (−13 , 1915 ) מהמרכז p ולכן המוקד שוכן מרחק y−פרבולה היא סימטרית סביב ציר ה

(−13 , 1915 +p)

=(−13 , 1915 +(−512 ))

פשט

(−13 , 1720 )

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

amplitude of cos(2x+5)

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