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3-x^2=y, x+1=y

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3−x²=y, x+1=y

Solution

(

`x`=−2,	`y`=−1
`x`=1,	`y`=2

)

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Solution steps

One step at a time

[

3−x²=y

x+1=y

]

Subtract the equations

3−x²=y

−

x+1=y

3−x²−(x+1)=y−y

Simplify

−x²−x+2=0

Solve −x²−x+2=0: x=−2, x=1

Plug the solutions x=−2, x=1 into 3−x²=y

For 3−x²=y, subsitute x with −2: y=−1

For 3−x²=y, subsitute x with 1: y=2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for 3−x²=y, x+1=y are

(

`x`=−2,	`y`=−1
`x`=1,	`y`=2

)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

3-x^2=y, x+1=y

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