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f(x)={

sin(`x`)	`x`<0
2`x`	`x`≥ 0

Solution

Domain: −∞ <x<∞

X Intercepts: (2πn, 0), (π+2πn, 0), (0, 0), Y Intercepts: (0, 0)

Asymptotes: Slant y=2x

Monotone Intervals: Increasing:2πn≤ x<π2 +2πn, Decreasing:π2 +2πn<x<3π2 +2πn, Increasing:3π2 +2πn<x<2π+2πn, Increasing:0<x<∞

Interval Notation

Domain: (−∞ , ∞ )

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Domain of {sin(x):x<0, 2x:x≥ 0} : −∞ <x<∞

Axis interception points of {sin(x):x<0, 2x:x≥ 0}: X Intercepts: (2πn, 0), (π+2πn, 0), (0, 0), Y Intercepts: (0, 0)

Asymptotes of {sin(x):x<0, 2x:x≥ 0}: Slant: y=2x

Monotone Intervals of {sin(x):x<0, 2x:x≥ 0}: Increasing:2πn≤ x<π2 +2πn, Decreasing:π2 +2πn<x<3π2 +2πn, Increasing:3π2 +2πn<x<2π+2πn, Increasing:0<x<∞

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היי, לשאול שאלה לגבי f(x)={

sin(`x`)	`x`<0
2`x`	`x`≥ 0

או בחר למטה

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

`x`²	`x`<−2
ln(`x`+5)	`x`≥−2

√`x`+2	`x`<1
`xx`²−6`x`+8	`x`≥1

√`x`²−4	`x`<0
`x`³−`x`	`x`≥0

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