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substitution y^{\prime\prime\prime}-y^{\prime}=x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

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^□√☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

laplace bernoulli substitution linear exact

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substitution y^{′ ′ ′}−y^′=x

Solution

y=c₁e^x−c₂e^−x−x²2 +c₃

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y′ ′ ′ −y′ =x

Solve using substitution: y=c₁e^x−c₂e^−x−x²2 +c₃

y=c₁e^x−c₂e^−x−x²2 +c₃

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

substitution y^{\prime\prime\prime}-y^{\prime}=x

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