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derivative of (x-1-i(x+1-i))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx ((x−1−i)(x+1−i))

Solution

2x−2i

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Solution steps

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ddx ((x−1−i)(x+1−i))

Simplify (x−1−i)(x+1−i): (x²−2)−2ix

=ddx ((x²−2)−2ix)

Apply the Sum/Difference Rule: (f±g)′=f ′±g′

=ddx (x²−2)−ddx (2ix)

ddx (x²−2)=2x

ddx (2ix)=2i

=2x−2i

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (x-1-i(x+1-i))

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