inverse of sqrt(4/x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inverse laplace 4x²−2x+12x+3

Solution

2δ′(t)−4δ(t)+132 e^−3t2

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L⁻¹{4x²−2x+12x+3 }

4x²−2x+12x+3 קח את השבר החלקי של: 2x−4+132x+3

=L⁻¹{2x−4+132x+3 }

Use the linearity property of Inverse Laplace Transform:
For functions f(s), g(s) and constants a, b: L⁻¹{a·f(s)+b·g(s)}=a·L⁻¹{f(s)}+b·L⁻¹{g(s)}

=2L⁻¹{x}−L⁻¹{4}+L⁻¹{132x+3 }

L⁻¹{x}: δ′ (t)

L⁻¹{4}: 4δ(t)

L⁻¹{132x+3 }: 132 e^−3t2

=2δ′ (t)−4δ(t)+132 e^−3t2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of sqrt(4/x)

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