inverse of laplace (10)/((x-1)(x^2+9))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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projection (

), (

−8

)

Solution

(

−135

−265

)

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lim_{x→ ∞}(x(x²+1)² )

a+b=a(1+ba ) :השתמש בחוק האלגברי הבא
x(x²+1)² =x(x²(1+1x² ))²

=lim_{x→ ∞}(x(x²(1+1x² ))² )

x(x²(1+1x² ))² פשט את: 1x³(1x² +1)²

=lim_{x→ ∞}(1x³(1x² +1)² )

lim_x→a[f(x)g(x) ]=lim_x→af(x)lim_x→ag(x) , lim_x→ag(x)≠0
למעט מקרים של ביטוי לא מוגדר

=lim_{x→ ∞}(1)lim_{x→ ∞}(x³(1x² +1)²)

lim_{x→ ∞}(1)=1

lim_{x→ ∞}(x³(1x² +1)²)=∞

=1∞

c∞ =0 :אריתמטיקה של גבולות אינסופיים

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of laplace (10)/((x-1)(x^2+9))

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