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foci (y^2}{25}-\frac{x^2)/9 =1

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foci y²25 −x²9 =1

Solution

(0, √34), (0, −√34)

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Hyperbola Foci

For an up-down facing hyperbola, the Foci (focus points) are defined as (h, k+c), (h, k−c),
where c=√a²+b² is the distance from the center (h, k) to a focus

(h, k+c), (h, k−c)

Calculate Hyperbola properties

y²25 −x²9 =1: Up-down Hyperbola with (h, k)=(0, 0), a=5, b=3

(0, 0+c), (0, 0−c)

Compute c:

c=√5²+3²: √34

(0, 0+√34), (0, 0−√34)

Refine

(0, √34), (0, −√34)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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foci (y^2}{25}-\frac{x^2)/9 =1

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qb-banner-title

foci (y^2}{25}-\frac{x^2)/9 =1

Solution

Solution steps

Number Line

Graph