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x+19=(3(2x+4))/4

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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x+19=3(2x+4)4

Solution

x=32

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x+19=3(2x+4)4

Multiply both sides by 4

4x+76=3(2x+4)

Expand 3(2x+4): 6x+12

4x+76=6x+12

Move 76 to the right side

4x=6x−64

Move 6x to the left side

−2x=−64

Divide both sides by −2

x=32

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

x+19=(3(2x+4))/4

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