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15=3(2x-15)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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x⁴−5x²+4=0

Solution

x=2, x=−2, x=1, x=−1

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x⁴−5x²+4=0

u²=x⁴ וכן u=x² כתוב את המשוואות מחדש, כאשר

u²−5u+4=0

u²−5u+4=0 פתור את: u=4, u=1

u=4, u=1

Substitute back u=x², solve for x

x²=4 פתור את: x=2, x=−2

x²=1 פתור את: x=1, x=−1

The solutions are

x=2, x=−2, x=1, x=−1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

15=3(2x-15)

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